🎯 Adventure 12 — Projectile Motion (Solution)

Solution key shown in the boxes. Charts on the right.

Part 1 – A Ball Thrown Straight Up

1) At what time does the ball reach its greatest height?

2) What is the maximum height?

3) What is the velocity at t = 0 seconds?

4) What is the velocity at t = 6 seconds?

5) At what time is the velocity equal to zero?

6) At that moment (v = 0), what is the ball doing?

7) Complete the sentence: “At maximum height, the velocity is ____.”

8) What is the acceleration (constant) during the whole flight?

9) Is acceleration ever zero during the flight? (yes/no)

10) What is the cannonball’s initial vertical velocity?

11) What is the maximum height reached?

12) When does it stop rising (vertical v = 0)?

13) Compared to the straight-up throw, the cannonball’s vertical motion is…

14) What is the total time in the air?

15) Suppose the cannon ball moves horizontally at a constant speed of:

(teacher choice)

16) How far will it travel horizontally (range)?

(depends on #15)

17) At maximum height, the vertical velocity is:

18) At maximum height, the acceleration is:

19) The time to reach the maximum depends on the ___ motion.

20) The range depends on the ___ motion.

21) In this example, the vertical launch speed is:

22) For maximum range at fixed speed (no air resistance), the best launch angle is:

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