df(x), then find df(x)/dx.
Keep dx as a tiny number, and remember: terms with dx² and dx³ vanish as dx → 0.
Tip: Think “new pieces only.” The original blue square/cube is already x² or x³.
Only count what gets added when each side grows from x to x + dx.
f(x)=x²
df(x):
df(x) = df(x) = dx:
df(x)/dx = dx → 0. Cross out any terms that vanish and write the derivative:
d(x²)/dx = f(x)=x³
x to x+dx:
x²·dx? x·dx²? dx³? df(x):
df(x) = dx (so dividing is easy):
df(x) = dx:
df(x)/dx = dx → 0. Cross out vanishing terms and write the derivative:
d(x³)/dx =
Check: your final answers should be 2x and 3x².